(II) V is a vector 14.3 units in magnitude and points at an angle of 34.8" above the negative x axis (a) Sketch this
vector. (b) Find V, and V,. (c) Use V, and V, to obtain
(again) the magnitude and direction of V. [Nore: Part (c)
is a good way to check if you've resolved your vector
Correctly.

The step-down transformer gives a current of 10a at 24v if the primary voltage is 240v calculate the 1_primary current 2_the power input 3_the power output

Around faucet handle is part of a(n) a. lever b. screw c. inclined plane d. wheel and axle

The x-coordinate of a particle in curvilinear motion is given by x = 3.1t3 - 4.9t where x is in feet and t is in seconds. the y-component of acceleration in feet per second squared is given by ay = 2.3t. if the particle has y-components y = 0 and vy = 5.0 ft/sec when t = 0, find the magnitudes of the velocity v and acceleration a when t = 1.8 sec. sketch the path for the first 1.8 seconds of motion, and show the velocity and acceleration vectors for t = 1.8 sec. answers: v = ft/sec a = ft/sec2