An upward force is applied to a 6.0-kilogram box. this force displaces the box upward by 10.00 meters. what is the work done by the force on the box?

The correct answer to the question is 588 Joule i.e the work done by the force on the box is 588 Joule.

CALCULATION:

As per the question, the mass of the box m = 6.0 kg.

The upward displacement of the box is 10.00 m.

Hence, the height of the box h = 10 .00 m.

We are asked to calculate the work done by the force on the box.

When the upward force was applied to the box, the box moves up to a height of 10.00 m. Hence, the work done by the ball is nothing else than the potential energy gained by the ball.

The potential energy gained by the ball is calculated as -

                                       Potential energy P.E = mgh

                                                                          = 6 × 9.8 × 10 Joule

                                                                         = 588 Joule.

Here, g is known as the acceleration due to gravity and its value is .

Joule is the unit of energy.

We know that work done W = Potential energy gain.

Hence, the work done by the force on the box is 588 Joule.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz