Physics, 07.10.2020 22:01 elijahworley

A small, 29 gram pith balls carrying 2 nC of charge is dangling from an insulating string. Another charged pith balls carrying an unknown amount of charge is brought close to the first ball, causing it to shift away. When everything is in equilibrium, the two balls are horizontally separated by distance of 5 cm, and the string is tilted about 11 degrees away from the vertical direction. How much charge is on the second ball

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Answer from: penelopymorales

$q_2=7.67\times 10^{-6}\ C$

Explanation:

Given that,

Mass of a pitch ball, m = 29 g = 0.029 kg

Charge on one pitch ball, q₁ = 2 nC

Another charged pith balls carrying an unknown amount of charge is brought close to the first ball, causing it to shift away. When everything is in equilibrium, the two balls are horizontally separated by distance of 5 cm or 0.05 m, and the string is tilted about 11 degrees away from the vertical direction.

At equilibrium,

$T\cos\theta=mg\ .....(1)\\\\\text{and}\\\\T\sin\theta=\dfrac{kq_1q_2}{d^2}\ ....(2)$

Where q₂ is the change on the second ball

Dividing equation (2) by (1) we get :

$\tan\theta=\dfrac{kq_1q_2}{d^2mg}$

Solving for q₂, we get :

$q_2=\dfrac{\tan\theta d^2 mg}{kq_1}\\\\q_2=\dfrac{\tan(11)\times 0.05^2\times 0.029\times 9.8}{9\times 10^9\times 2\times 10^{-9}}\\\\q_2=7.67\times 10^{-6}\ C$

So, the charge on the second ball is $7.67\times 10^{-6}\ C$ .

Answer from: Quest

La olla es de metal por que se calienta mas rápido, y las manijas son de madera por que así no se calientas y tienden a estar mas frías.

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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A small, 29 gram pith balls carrying 2 nC of charge is dangling from an insulating string. Another c...