Physics, 07.10.2020 02:01 angelisabeast5430
A horse 1 m tall running towards a tree at a constant velocity of 20m/s,
there was a baboon on the tree which is 3m tall, if the baboon falls exactly on
the back of the horse and sped away with baboon at its back.
Calculate
I) how far was the horse from the tree and the time the baboon
falls on the horse.
Answers: 2
Physics, 21.06.2019 17:00, pinkfluffyunicorns
These models show the electron structures of two different nonmetal elements. which element is likely more reactive, and why? element 1 is more reactive because it has fewer electron shells and is toward the top of its group on the periodic table. element 1 is more reactive because it has more electrons in its valence shell and is farther to the right on the periodic table. element 2 is more reactive because it does not have a valence shell close to the nucleus, so it will attract electrons. element 2 is more reactive because it does not have a full valence shell, so it will attract electrons.
Answers: 2
Physics, 21.06.2019 23:20, stormserena
The 5-kg cylinder is initially at rest when it is placed in contact with the wall b and the rotor at a. if the rotor always maintains a constant clockwise angular velocity v = 6 rad> s, determine the initial angular acceleration of the cylinder. the coefficient of kinetic friction at the contacting surfaces b and c is mk = 0.2.
Answers: 3
Physics, 22.06.2019 18:30, kayleahrayne
Ablock of mass m slides on a horizontal frictionless table with an initial speed v0 . it then compresses a spring of force constant k and is brought to rest. the acceleration of gravity is 9.8 m/s2. how much is the spring compressed x from its natural length? 1) x = v0*sqrt(k/(mg)) 2) x=v0*sqrt(m/k) 3) x=v0*((mk)/g) 4) x=v0*sqrt(k/m) 5) x=v0*(m/kg) 6) x=v0*sqrt((mg)/k) 7) x=(v0)^2/(2g) 8) x=v0*(k/(mg)) 9) x=(v0)^2/(2m) 10) x=v0*((mg)/k)
Answers: 3
A horse 1 m tall running towards a tree at a constant velocity of 20m/s,
there was a baboon on the...
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