What must be the acceleration of a train in order for it to stop from 12m/s in a distance of 541m? Please help!!

The acceleration of the train must be - 0.133 m/s²

Explanation:

A train in order for it to stop 12 m/s in a distance if 541 m

That means the initial velocity of the train is 12 m/s

Its final velocity is zero (stop)

The distance it covers is 541 m

P.S. This is part of the answer of another user this is not my knowledge.

But Hope I helped you

-0.133 m/s²

Explanation:

Given:

Δx = 541 m

v₀ = 12 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (12 m/s)² + 2a (541 m)

a = -0.133 m/s²

i wanna say it’s between b and d, leaning more towards b.

hi i’m sorry to call us today so we will get back with y’all and we will have to do it haha omg was the day