¿Qué cantidad de calor se debe suministrar a 500 g de un pedazo de cobre para elevar su temperatura de 30°C a 250°C? (Ce=0,09 cal/g°C)

9900 cal or 41421.6 J

Explanation:

la cantidad de calor necesaria para elevar la temperatura de una sustancia viene dada por la fórmula:

Q = mcΔT

Donde Q = cantidad de calor, C = capacidad calorífica específica de la sustancia,Δ T = T2-T1, T2 = temperatura final, T1 = temperatura inicial

m = 500 g, T2 = 250 °C, T1 = 30 °C, C = 0,09 cal/g°C

ΔT = T2 - T1 = 250 - 30 = 220 °C

Q = 500 × 0.09 × 220 = 9900 cal

1 cal = 4.184 J

Q = 9900 cal =

this is poiselle's equation from fluid mechanic in physics. mech eng

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