The pressure of an ideal gas is 4 atm. If the only change is to increase the temperature by a factor of 4, what will be the new pressure of the gas. Use (Pv=NkT)

The new pressure is 4 times of the initial pressure.

Explanation:

Given that,

The pressure of an ideal gas is 4 atm.

We need to find the change in the pressure of the gas if the temperature by a factor of 4.

We know that,

PV = nKT ....(1)

P = pressure, V = volume, T = temperature

Let P' is the new pressure of the gas. So,

P'V= nK(4T) ......(2)

Dividing equation (1) and (2) we get :

It means that the new pressure is 4 times of the initial pressure.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west