Even at rest, the human body generates heat. The heat arises because of the body's metabolism - that is, the chemical reactions that are always occurring in the body to generate energy. In rooms designed for use by large groups, adequate ventilation or air conditioning must be provided to remove this heat. Consider a classroom containing 138 students. Assume that the metabolic rate of generating heat is 128 W for each student and that the heat accumulates during a 60-minute lecture. In addition, assume that the air has a molar specific heat of CV = 5/2R and that the room (volume = 1190 m^3, initial pressure = 1.01 x 10^5 Pa, and initial temperature = 21.0 °C) is sealed shut. If all the heat generated by the students were absorbed by the air, by how much would the air temperature rise?

The  value  is  

Explanation:

From the question we are told that

   The number of students is  

   The metabolic rate for each student is  

   The time duration is  

   The  molar specific heat of air is  

   The volume  is

    The  pressure is  

     The  initial temperature is

Generally the metabolic rate of the students is

=>          

=>          

The  total heat generated by the students is  

=>          

=>          

From the ideal gas law  we can evaluate n (number of moles ) as  

Here  R is the gas constant with value  

So

=>  

Generally the heat generated is mathematically represented as      

=>    

=>    

=>    

=>    

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

a. are