What is the acceleration of a baseball that has a final velocity of 15.0 m/s when it crosses the plate 2.0 seconds after leaving the pitchers hand? The initial velocity is 0./0 m/s and the baseball is traveling forward.

7.5m/s²

Explanation:

Acceleration is the change in velocity of a body with respect to time.

acceleration = change in velocity/time

a = Δv/t

a = v-u/t

v is the final velocity = 15.0m.s

u is the initial velocity = 0.0m/s

t is the time = 2.0s

Substituting the values to get a

a - 15-0/2

a = 15/2

a = 7.5m/s²

Hence the acceleration of the baseball is 7.5m/s²