Two small objects each with a net charge of +Q exert a force of magnitude F on each other. We replace one of the objects with another whose net charge is + 4Q. We move the +Q and +4Q charges to be 3 times as far apart as they were. What is the magnitude of the force on the +4Q charge ? A. F

B. 4F

C. 4F/3

D. 4F/9

E. F/3

F'= 4F/9

Explanation:

Two small objects each with a net charge of +Q exert a force of magnitude F on each other. If r is the distance between them, then the force is given by :

...(1)

Now, if one of the objects with another whose net charge is + 4Q is replaced and also the distance between +Q and +4Q charges is increased 3 times as far apart as they were. New force is given by :

.....(2)

Dividing equation (1) and (2), we get :

Hence, the correct option is (d) i.e. " 4F/9"

explanation:

newton's third law, for every action there is an equal and opposite reaction.