an arrow is launched straight up from the ground with an initial velocity of 23.4 m/s. how long until it reaches its highest point?

Explanation:

Given that,

The initial velocity of an arrow is 23.4 m/s

We need to find the time taken by it to reach its maximum height. Let the maximum height is h.

Using third equation of motion to find height first.

At maximum height, v = 0

a = -g

Let t is the time to reach its maximum height. So, it can be calculated using second equation motion as follows :

Hence, it will take 2.35 seconds to reach its maximum height.

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

the answer is a. hope this .