The output of a automobile alternator is typically about 14V D. C. The headlight circuit draws about 4 Amps of current. Using Ohm's Law (V = IR), the resistance of the headlight bulb can be calculated. Suppose your alternator quits working as you are driving home. The battery voltage now supplying energy to the headlight bulb drops to 12V D. C. Assume the bulb resistance R remains constant (it won’t, but that is another story). Required:
How much current (in Amps) now flows through the bulb?

I = 3.42 A

Explanation:

Ohm's law gives a relationship between the potential difference and the current passing through a conductor. The formula of Ohm's Law is given as follows:

V = IR

where,

V = Voltage

I = Current

R = Resistance

Initially:

V = 14 volts

I = 4 A

R = ?

Therefore,

14 volts = (4 A)R

R = (14 volts)/(4 A)

R = 3.5 Ω

Now, when V becomes 12 volts and R remains constant:

V = IR

12 volts = I(3.5 Ω)

I = (12 volts)/(3.5 Ω)

I = 3.42 A

answer; /// the above statement is (true);

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.