Suppose a radio signal (light) travels from Earth and through space at a speed of 3 × 10^8/ (this is the speed of light in vacuum). How far (in meters) into space did the signal travel during the first 10 minutes?

Speed is the rate of distance over time.

The signal will travel meters in the first 10 minutes

The given parameters are:

---the speed of light

-- the time of travel

The relationship between speed, distance (d) and time is:

Make d the subject

Substitute values for t and s

Convert minutes to seconds

So, we have:

Rewrite as:

Hence, the signal will travel meters in the first 10 minutes

Read more about speed at:

link

Explanation:

we know that

s=vt here v is the speed and s is distance covered by the signals

given data

v=3*10^8

t=10 min we have to convert it into seconds

1 minute=60 seconds

so

10 minutes =10*60/1 =600 seconds

now putting the value of v and t we can find the value of s

s=vt

s=3*10^8*600

s=1.8*10^11m

i hope this will help you

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y

friction

explanation:

they us to move forward and backwards