The Concord jetliner achieves a lift-off speed of 112 m/s in 20.0 seconds, starting from rest and traveling due east. What is the magnitude and direction of the average acceleration?

5.6 m/s

Explanation:

The acceleration of any possible is the ratio of the velocity of the particle with respect to the time the particle takes in moving. It is mathematically represented as

a = v/t, with m/s² as it's unit, where

v = velocity in m/s

t = time taken in seconds

a = acceleration in m/s²

From the explanation above, we were given in the question that, the speed is 112 m/s and the time if took is 20 seconds, thus, the acceleration is

a = 112/20

a = 5.6 m/s²

Therefore, the magnitude of the acceleration is 5.6 m/s²

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.