If you were standing at the center of curvature in front of a concave mirror, what image would be projected?
the image would be upside down, would look as tall as you, and would be at the same distance from the mirror as you are.
the image would be upright, would look shorter than you, and would be closer to the mirror than you are.
the image would be upside down, would look shorter than you, and would be closer to the mirror than you are.
the image would be upright, would look as tall you, and would be at the same distance from the mirror as you are.

The image would be upside down, would look as tall as you, and would be at the same distance from the mirror as you are.

Explanation:

As we know that the object position is at center of curvature of the mirror

So here the distance is given as

now by mirror formula of relation between distance of image and distance of object

so image will form at the position of object itself

Now we will say that the magnification of the object will be

so image will be upside down and same as that the height of object

so correct answer would be

The image would be upside down, would look as tall as you, and would be at the same distance from the mirror as you are.

i think the correct answer from the choices listed above is option c. when the kinetic energy of particles in a liquid state decreases

explanation:

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.