A 28-g rifle bullet traveling 190 m/s embeds itself in a 3.1-kg pendulum hanging swing upward l an arc. Determine the vertical and horizontal components of the pendulum's maximum displacement.

V = 0.15m

H = 0.85m

Explanation:

We will be using the conservation of momentum to solve the problem.

m(i).v(i) = m(f).v(f) where

0.028 * 190 = 3.1 * v(f)

v(f) = 5.32/3.1

v(f) = 1.72 m/s

next, we use the conservation of energy to find the vertical displacement.

½mv² = mgh

½v² = gh, making h the subject of formula, we have

h = v²/2g

h = 1.72²/ 2 * 9.81

h = 2.9584 / 19.62

h = 0.15 m

The height, h is the vertical displacement.

Next, we find the angle of the pendulum at the top of the swing.

Φ = cos^-1 [(2.5 - 0.15)/2.5] *the height at which the pendulum is hanging is not given, so I assumed it to be 2.5m, yo can substitute that for whatever it is

Φ = cos^-1(2.35/2.5)

Φ = cos^-1 (0.94)

Φ = 19.95°

This gotten angle is used to find the horizontal displacement

x = 2.5 sinΦ

x = 2.5 sin 19.95

x = 2.5 * 0.34

x = 0.85 m

answer would be d.) i hope this

explanation:

the answer is a 3.8cm

explanation: