A proton is accelerated to 225V. Its de-Broglie wavelength is: a. 1.91 pm
b. 0.2 pm
c. 3 pm
d. 0.4 pm

The  value  is  

Explanation:

From the question we are told that

  The  potential of the proton is  

Generally the momentum of the particle is mathematically represented as

Here  e is the charge on the proton with value  

      m is the mass of the proton with value  

So

=>    

So the de-Broglie wavelength isis mathematically represented as

Here  h is the Planck's  constant with value  

=>  

=>

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

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