A man standing on a weighing machine in a lift records his weight in the machine as under: (i) w1 when the lift acceleration upwards at 5 m/s2 (ii) w2 when the lift acceleration downwards at 5 m/s2 (iii) w3 when the lift moves up at 5 m/s (iv) w4 when the lift moves down at 5 m/s Which of the following gives a correct relation between their relative values. (a) w1 > w2 > w3 > w4 (b) w1 = w2 > w3 > w4 (c) w1 w3 = w4 < w1

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Iassume the answer is 75 feet. inwards to outwards rather than outwards to inwards. probably be 75.hachures are stokes drawn in direction of the steepest slope. a series of short parallel lines drawn on a map to indicate topographic relief. it is actually called hachures on contour lines. the small marks in the center of the feature are called hachures.observe the picture attached