Physics, 07.09.2020 03:01 KindaSmartPersonn
Find the resultant of the following forces by component method: F1 =12N, south; F2 =24N, 30° north of west; F3 = 15N, 75° south of west; and F4 = 32 N, 50° south of east.
Answers: 2
![\vec R = -16.099\,\hat{i} -27.002\,\hat{j}\,\,[N]](/tpl/images/0744/7564/3ea65.png)
.
- Resultant, measured in newtons.
- i-th x-Component, measured in newtons.
- i-th y-Component, measured in newtons.
, South:![\vec F_{1} = -12\,\hat{i}\,\,[N]](/tpl/images/0744/7564/24656.png)
, 
North of west:![\vec F_{2} = 24\cdot (-\cos 30^{\circ}\,\hat{i}+\sin 30^{\circ}\,\hat{j})\,[N]](/tpl/images/0744/7564/9310e.png)
![\vec F_{2} = -20.785\,\hat{i}+12\,\hat{j}\,\,[N]](/tpl/images/0744/7564/77a32.png)
, 
South of west:![\vec F_{3} = 15\cdot (-\cos 75^{\circ}\,\hat{i}-\sin 75^{\circ}\,\hat{j})\,\,[N]](/tpl/images/0744/7564/bbdda.png)
![\vec F_{3} = -3.883\,\hat{i}-14.489\,\hat{j}\,\,[N]](/tpl/images/0744/7564/19192.png)
, 
South of east:![\vec F_{4} = 32\cdot (\cos 50^{\circ}\,\hat{i}-\sin 50^{\circ}\,\hat{j})\,\,[N]](/tpl/images/0744/7564/19225.png)
![\vec F_{4} = 20.569\,\hat{i} -24.513\,\hat{j}\,\,[N]](/tpl/images/0744/7564/25d49.png)
![\vec R = (-12-20.785-3.883+20.569)\,\hat{i}+(12-14.489-24.513)\,\hat{j}\,\,[N]](/tpl/images/0744/7564/1c6b0.png)
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Find the resultant of the following forces by component method: F1 =12N, south; F2 =24N, 30° north o...
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