What is the displacement of a car with an acceleration of 4.00 m/s2 as it increases. its speed from 10.0 m/s to 30.0 m/s ?

100 m.

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 10 m/s

Final velocity (v) = 30 m/s

Acceleration (a) = 4 m/s²

Displacement (D) =?

Next, we shall determine the time.

This can be obtained as follow:

Acceleration is defined as the rate of change of velocity with time. Mathematically, it is expressed as:

a = (v – u) / t

Where

a is the acceleration.

u is the initial velocity.

v is the final velocity.

t is the time.

With the above formula, we can obtain the time as follow:

Initial velocity (u) = 10 m/s

Final velocity (v) = 30 m/s

Acceleration (a) = 4 m/s²

Time (t) =?

a = (v – u) / t

4 = (30 – 10)/t

4 = 20/t

Cross multiply

4 × t = 20

Divide both side by 4

t = 20/4

t = 5 secs.

Finally, we shall calculate the displacement of car as illustrated below:

Velocity is defined as rate of change of displacement with time. Mathematically, it can be expressed as:

(v – u) = D/ t

Where:

u is the initial velocity.

v is the final velocity.

t is the time.

D is the displacement.

With the above formula, we can calculate the displacement of the car as follow:

Initial velocity (u) = 10 m/s

Final velocity (v) = 30 m/s

Time (t) = 5 s.

Displacement (D) =?

(v – u) = D/ t

(30 – 10) = D/5

20 = D/5

Cross multiply

D = 20 × 5

D = 100 m

Therefore, the displacement of the car is 100 m

50 inches should be the resultant vector

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.