Estimate the magnitude of the drift speed in a wire that carries a current of 1A. The wire has radius 2mm and the number of electrons per unit volume of free electrons is n= 10 28 m -3 Cross-sectional area of the wire is A = πr 2

V = 4.6 × 10^20 m/s

Explanation:

Given that the magnitude of the drift speed V in a wire that carries a current I of 1A. The wire has radius 2mm and the number of electrons per unit volume of free electrons is n= 10 28 m -3 Cross-sectional area of the wire is A = πr 2

Convert the radius from mm to m by dividing it by 1000. Substitute it in the below formula

The cross sectional area A = π × (0.002)^2

A = 1.257 × 10^-5 m^2

The formula to use is:

I = VneA

Substitutes all the parameters into the formula

1 = V × 10^23 × 1.67×10^-19 × 1.257×10^-5

1 = 2.16 × 10^-21V

V = 1 / 2.16 × 10^-21

V = 4.6 × 10^20 m/s

hello there!

your answer is a “generator”

a generator does not create energy but instead it transforms it.

it’s basically a motor working in reverse.

this is a good question! i'll do some research and come back when i have the answer!