A particle has a velocity of v = 4 m/s and acceleration a = 10 m/s2. What is the distance traveled in 1 sec?

The distance traveled by the particle after 1 second is 9m.

Explanation:

Given;

velocity of the particle, v = 4 m/s

acceleration of the particle, a = 10 m/s²

time of motion of the particle, t = 1 second

distance traveled by the particle, d = ?

The distance traveled by the particle is given by;

d = vt + ¹/₂at²

d = (4 x 1) + ¹/₂(10)(1)²

d = 9 m

Therefore, the distance traveled by the particle after 1 second is 9m.

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2