answers If the motor is to accelerate the elevator car upward at 1.8 m/s2, how much torque must it generate

Hello your question is incomplete attached is the missing diagram and solution

One elevator arrangement includes the passenger car, a counterweight, and two large pulleys, as shown in (Figure 1). Each pulley has a radius of 1.2 m and a moment of inertia of 410 kg⋅m2. The top pulley is driven by a motor. The elevator car plus passengers has a mass of 3000 kg, and the counterweight has a mass of 2600 kg.

a) If the motor is to accelerate the elevator car upward at 1.8 m/s2, how much torque must it generate? Express your answer to two significant figures and include appropriate units.

Answer : 6030 N.m ≈ 6000 N.m

Explanation:

To determine how much torque the motor accelerating at 1.8 m/s^s will generate we will have to determine T1 ( tension  generated for upward acceleration in the rope  ) and Tg ( tension  generated in the rope when there is a counterweight accelerating downwards)

Torque in the pulley (T2) = (T1 - Tg ) r

torque generated by motor = T1 + T2 = 1230 + 4800 = 6030 N.m to two significant figures = 6000 N.m

r = 1.2

a = 1.8

attached below is the remaining part of the solution

The answer is water molecules are split.cellular respiration and photosynthesis are complement  reactions to each other. these are reverse reactions. in cellular respiration glucose and oxygen yield water and carbon dioxide. so, when respiration begins,  glucose molecules are split. in the opposite reaction - in photosynthesis, carbon dioxide and water yield glucose and oxygen. thus,  when respiration begins, water molecules are split.

Iknow the first part it is the average star i am not 100% sure