Super fine 40-gauge copper wire has a diameter of only 0.080mm and weighs only 44.5/gkm. Suppose a spool of 40-gauge wire weighs 570.g less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.

mount of wire used=12.808989 Km

Amount of wire used=12808.989 m

Explanation:

Given Data:

Diameter of wire=d=0.080 mm=0.00008 m

Weight of wire per unit length=44.5 g/km

Spool weighs=M=570 g

Required:

Amount of wire used=L=?

Solution:

Formula is:

The above expression is mathematical model of finding how much wire is used. just put the Value of M we will get the answer.

Amount of wire used=12.808989 Km

Amount of wire used=12808.989 m

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz