scott and jafar are ready to work a problem. in this simulation, assume the coordinates of the points are as follows. a (0 s, 30 m); b (10 s, 50 m); c (20 s, 38 m); d (30 s, 0 m); e (40 s, −38 m); and f (50 s, −50 m) recall the definitions of average speed, vavg ≡ d δt , and average velocity in the x direction, vx ,avg ≡ δx δt . find the average velocity from circled a to circled b.

Explanation:

point a represents time 0 and position coordinate 30

point b represents time 10 s , and position coordinate 50 m .

time elapsed = 10 - 0 = 10 s .

displacement = 50 m - 30 m

= 20 m

average velocity = displacement / time elapsed

= 20 / 10

= 2 m /s .

concave lenses are used here. they spread the light out before it reaches the convex lens in the eye, therefore letting the image focus directly on the retina. hyperopia is known to you probably as farsightedness.

lol

explanation: