a ballon filled with nitrogen gas has a small leak. Another ballon filled with hydrogen gas has an identical leak. How much faster will the hydrogen balloon deflate

4 times that of nitrogen gas, N2.

Explanation:

Let R1 be the rate of diffusion of nitrogen gas, N2.

Let R2 be the rate of diffusion of Hydrogen gas, H2.

Let M1 be the molar mass N2

Let M2 be the molar mass of H2.

Next, we shall determine the molar mass of N2 and H2.

This is illustrated below below:

Molar mass of N2 (M1) = 2 x 14 = 28 g/mol

Molar mass of H2 (M2) = 2 x 1 = 2 g/mol

Finally, we shall determine the rate of diffusion of Hydrogen gas, H2 as follow:

R1/R2 = √(M2/M1)

M1 = 28

M2 = 2

R1/R2 = √(M2/M1)

R1/R2 = √(2/28)

R1/R2 = √(1/14)

R1/R2 = 0.27

Cross multiply

R1 = R2 × 0.27

Divide both side by 0.27

R2 = R1/0.27

R2 = R1 × 1/0.27

R2 = R1 × 4

R2 = 4R1

Therefore, the rate of diffusion of H2 (R2) is 4 times that of N2 (R1)

radiation

explanation:

heat is transmitted by radiation

continuous conducting path for current, power supply