I WILL GIVE BRAINLIEST Your friend stands on the roof of her house, which is 12.2 m off the ground, and kicks a soccer ball to you so that it is initially moving horizontally at 13.9 m/s. What is its speed as it hits the ground? The time is 1.58 seconds.

16.74 m/s

Explanation:

From the question, the parameters given are:

Height h = 12.2 metres

Initial velocity U = 13.9 m/s

Time t = 1.58 s

The range or distance covered by the ball will be

R = u^2/g

Where g = 9.8 m/s^2

R = 13.9^2/9.8

R = 193.21/9.8

R = 19.72 m

Let first calculate the acceleration by using the formula below

R = Ut + 1/2at^2

Substitute all the parameters into the formula

19.72 = 13.9 × 1.58 - 1/2 × a × 1.58^2

19.72 = 21.962 - 1.2482a

Collect the like terms

-1.2482a = 19.72 - 21.962

- 1.2482a = - 2.242

a = 2.242/1.2482

a = 1.796 m/s^2

Using equation 1 to find the final speed

V = U + at

V = 13.9 + 1.796 × 1.58

V = 13.9 + 2.838

V = 16.74 m/s

Therefore, it hit the ground at speed 16.74 m/s

i'm thinking more like energy

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