A 0.40 kg mass hangs on a spring with a spring constant of 12 N/m. The system oscillated with a constant amplitude of 12 cm. What is the maximum acceleration of the system

The maximum acceleration of the system is 359.970 centimeters per square second.

Explanation:

The motion of the mass-spring system is represented by the following formula:

Where:

- Position of the mass with respect to the equilibrium position, measured in centimeters.

- Amplitude of the mass-spring system, measured in centimeters.

- Angular frequency, measured in radians per second.

- Time, measured in seconds.

- Phase, measured in radians.

The acceleration experimented by the mass is obtained by deriving the position equation twice:

Where the maximum acceleration of the system is represented by .

The natural frequency of the mass-spring system is:

Where:

- Spring constant, measured in newtons per meter.

- Mass, measured in kilograms.

If and , the natural frequency is:

Lastly, the maximum acceleration of the system is:

The maximum acceleration of the system is 359.970 centimeters per square second.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

i would say