The piston of a hydraulic elevator used for lifting trucks has a 0.3m radius. What pressure is required to lift a truck of 2500 kg mass? What force was applied to the small piston if it has a radius of 3cm?

1. 88370.45 N/

2. 2500 N.

Explanation:

Pressure, P, is define as the force, F, per unit area, A, applied on/ by an object.

i.e P =

1. The area, A, of the piston of the hydraulic elevator can be determined by;

A =

where r is the radius of the piston.

A = ×

  = × 0.09

  = 0.2829

Pressure required to lift a truck of 2500 kg mass can be determined as;

P =

F = W = mg

  = 2500 × 10

  = 25 000 N

So that,

P =

  = 88370.45 N/

The pressure required is 88370.45 N/.

2. =

 Area of small piston =

                                   = ×

                                   = 0.02829

So that,

=

= 2500 N

The force applied to the small piston is 2500 N.

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i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!