The location of a particle is measured with an uncertainty of 0.13 nm. One tries to simultaneously measure the velocity of this particle. What is the minimum uncertainty in the velocity measurement. The mass of the particle is 1.745×10-27 kg

The minimum uncertainty in the velocity is 232.57 m/s.

Explanation:

Given that,

Location of a particle with uncertainty = 0.13 nm

Mass of particle

We need  to calculate the minimum uncertainty in the velocity

Using heisenberg's uncertainty principle,

Put the value into the formula

Hence, The minimum uncertainty in the velocity is 232.57 m/s.

we need answer choices

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂