The heat of fusion of water is 79.5 cal/g. This means 79.5 cal of energy are required to: A) raise the temperature of 1 g of water by 1K
B) turn 1 g of water to steam .
C) raise the temperature of 1 g of ice by 1 K .
D) melt 1 g of ice .
E) increase the internal energy of 1 g of water by 1 J .

D) melt 1 g of ice

Explanation:

Heat of fusion is the energy required to change the state of a substance from solid state to liquid state at a constant pressure.

Heat of fusion of water occurs when solid ice acquires energy and turn into liquid water through a process known as melting.

Thus, if the heat of fusion of water is 79.5 cal/g, it means 79.5 cal of energy are required to melt 1 g of ice.

D) melt 1 g of ice

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be