The cylinder is displaced 0.17 m downward from its equilibrium position and is released at time t = 0. Determine the displacement y and the velocity v when t = 3.1 s. The displacement and velocity are positive if downward, negative if upward. What is the magnitude of the maximum acceleration?

Complete Question

The image of this question  is shown on the first uploaded image

a

b

c

Explanation:

From the question we are told that

      The maximum  displacement is  A =  0.17  m  

      The  time considered is  

     The spring constant is  

      The mass is  

Generally given that the motion which the cylinder is undergoing is a simple harmonic motion , then the displacement is mathematically represented as

Where is the angular frequency which is mathematically evaluated as

substituting values

So the displacement is at  t

Generally the velocity of a  SHM(simple harmonic motion) is mathematically represented as

substituting values

Generally the maximum acceleration is  mathematically represented as

substituting values

substituting values

do you have a formula possibly