An ideal gas absorbs 750 J of heat as it performs 625 J of work. What is the resulting change in temperature if there are 1.3 moles of the gas in the system

7.7°K

Explanation:

Using pV = NkT = nRT

U = CvNkT = Cv nRT

where:

Cv is a constant dependent on temperature (e.g. equal to 3/2 for a monatomic gas for moderate temperatures)

U is the internal energy

p is the pressure

V is the volume

n is the amount of gas (moles)

R is the gas constant, 8.314 J·K^−1mol^-1

T is the absolute temperature

N is the number of particles

k is the Boltzmann constant, 1.381×10^−23 J·K^−1

In your first problem, the energy difference between heat absorbed by the gas and the work performed is the energy lost to heat. So

∆E = Cv nR∆T

where ∆T is the temperature change

∆T = ∆E / (Cv nR)

= (750-625) / (3/2)(1.3)(8.314)

= 7.71° K

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s