Physics, 31.07.2020 16:01 maybellforever120215

Two children push on opposite sides of a door during play. Both push horizontally and perpendicular to the surface of the door. One child pushes with a force of 17.5 N at a distance of 0.59 m from the hinges, and the second child pushes at a distance of 0.47 m. What force must the second child exert to keep the door from moving? Assume friction is negligible.

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Answer from: Goldenstate32

F₂ = 21.97 N

Explanation:

this is a rotational equilibrium exercise, let's write the formula

∑ τ = 0

F₁ d₁ - F₂ d₂ = 0

force F₁ is 17.5 N and its distance d₁ = 0.59m, the distance d₂ = 0.47m

F₂ = F₁ d₁ / d₂

F₂ = 17.5 0.59 / 0.47

F₂ = 21.97 N

Answer from: Quest

Divide 108.2 x 10^6 into 1.5 x 10 and the result will be in au (astronomical units)

Answer from: Quest

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Two children push on opposite sides of a door during play. Both push horizontally and perpendicular...