Consider a transformer. used to recharge rechargeable flashlight batteries, that has 500 turns in its primary coil, 3 turns in its secondary coil, and an input voltage of 120 V. Randomized Variables Δ 33% Part (a) What is the voltage output Vs, in volts, of the transformer used for to charge the batteries? Grade Summar Deductions Potential sin tan) ( Submissions Attempts remain coso cotan) asin) acos() atan acotan)sinh( cosh)tanhcotanh0 % per attempt detailed view END Degrees Radians DEL CLEAR Submit Hint I give up! Hints:% deduction per hint. Hints remaining:I Feedback: 1% deduction per feedback. - 쇼 33%
Part (b) what input current ,. İn milliamps, is required to produce a 3.2 A output current? 33%
Part (c) What is the power input, in watts?

a) 0.72 V

b) 19.2 mA

c) 2.304 Watts

Explanation:

A transformer is used to step-up or step-down voltage and current. It uses the principle of electromagnetic induction. When the primary coil is greater than the secondary coil, the it is a step-down transformer, and when the primary coil is less than the secondary coil, the it is a step-up transformer.

number of primary turns = = 500 turns

input voltage = = 120 V

number of secondary turns = = 3 turns

output voltage = = ?

using the equation for a transformer

substituting values, we have

= 360/500 = 0.72 V

b) by law of energy conservation,

where

= input current = ?

= output voltage = 3.2 A

= output voltage = 0.72 V

= input voltage = 120 V

substituting values, we have

120 = 3.2 x 0.72

120 = 2.304

 = 2.304/120 = 0.0192 A

= 19.2 mA

c) power input =

==> 0.0192 x 120 = 2.304 Watts

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