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Physics, 26.07.2020 14:01 corbinfisher

At time t = 1, a particle is located at position (x, y) = (5, 2). If it moves in the velocity field F(x, y) = xy − 1, y2 − 11 find its approximate location at time t = 1.02.

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At time t = 1, a particle is located at position (x, y) = (5, 2). If it moves in the velocity field...

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