What is the magnetic force on a particle that has 0.000500 C of charge and is moving at 2.50 10m/s to the right through a magnetic field that is 4.20 T and pointing away from
you? Specify both magnitude and direction in your answer.

1.) F = 5.3×10^-3 N

2.) Positive y - direction

Explanation:

The parameters given are:

Charge q = 0.0005C

Velocity V = 2.5010 m/s

Magnetic field B = 4.2 T

Magnetic force F = BVqsinØ

F = BVq

since Ø = 90 degree

Substitute all the parameters into the formula

F = 4.2 × 2.5010 × 0.0005

Therefore, the magnetic force on a particle is F = 5.3 × 10^-3 N

2.) According to Fleming's left hand rule, the direction of the magnetic force will be perpendicular to the magnetic field which moving upward of the screen.

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

muscle endurance

explanation:

i can do 50 in a row ( but i get so tired after that)