A particle confined to a motion along the x axis moves with a constant acceleration of 2.5m/s2. Its velocity at t=0s is 6m/s. Find its velocity at t=4s.

v = 16 m/s

Explanation:

It is given that,

Acceleration of a particle along x -axis is

At t = 0s, its velocity is 6 m/s

We need to find the velocity at t = 4 s

It means that the initial velocity of the particle is 6 m/s

Let v is the velocity at t = 4 s

So,

v = u + at

So, the velocity at t = 4 s is 16 m/s.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force