A proton moves through a magnetic field at 21.5% of the speed of light. At a location where the field has a magnitude of 0.00627 T and the proton's velocity makes an angle of 147∘ with the field, what is the magnitude FB of the magnetic force acting on the proton? Use c=2.998×108 m/s for the speed of light and e=1.602×10−19 C as the elementary charge.
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Physics, 21.06.2019 22:30, jadalysrodriguez
The percent efficiency of a machine can never be 100% (or greater), because in the real world some energy is always converted into a. heat b. work c. input force d. output force
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A proton moves through a magnetic field at 21.5% of the speed of light. At a location where the fiel...
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