An airplane on a runway has an initial speed of 15 meters/second. What is its final velocity when it travels 600 meters on the runway with a constant acceleration of 6 meters/second2?

86.17m/s

Explanation:

Since the motion is of constant acceleration, we can use one of the equations of motion as follows;

v² = u² + 2as

Where;

v = final velocity of the airplane

u = initial velocity of the airplane

s = distance covered by the plane

a = acceleration

From the question,

u = 15m/s

s = 600m

a = 6m/s²

Substitute these values into the equation above as follows;

v² = 15² + 2(6)(600)

v² = 225 + 7200

v² = 7425

v = √7425

v  = 86.17m/s

Therefore, the final velocity of the airplane is 86.17m/s

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explanation:

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