a ball is rolling along a ground with a velocity of 10m/s and comes to rest after 8s. what is its acceleration

-1.25 m/s²

Explanation:

Use the formula a=(v-u)/t,

acceleration a = unknown

final velocity v= 0 m/s (rest)

initial velocity u = 10m/s

time t = 8s

a = (0-10)/8

a = -1.25 m/s²

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true is the correct answer

hope i