a wheel 0.35m in diameter rotates at 2200rpm. calculate its angular velocity in rad/s and its linear speed and acceleration of a point on the edge of the wheel. need help asap

( Angular Velocity = ( About ) 230 rad / s,

( Linear Speed = ( About ) 40.25 m / s,

( Acceleration = ( About ) 9290 m /

Explanation:

Here we want the angular velocity in radians per second, the linear velocity and acceleration.

The diameter = .35 meters, and thus we can conclude that the radius be half of that, or .175 meters. For part ( a ), or the calculation of the angular velocity, it is given that the diameter rotates at 2200 revolutions per minute - but we need to convert this into radians per second.

We can say that there are 2π radians for every minute, and for every minute there are 60 seconds. Therefore -

( a ) w = 2,200 rpm( 2π rads / rev )( 1 min / 60 sec )...

Hence, w = ( About ) 230 rad / s

_____

For this second part we can calculate the the linear velocity by multiplying the angular velocity ( omega ) by the radius r -

( b ) v = w( r ) - Substitute,

v = ( 230 rad / sec )( .175 m )...

v = ( About ) 40.25 m / s

_____

And for this last bit here, to find the acceleration we can simply take the angular velocity ( omega ) squared, by the radius r -

( c ) = w^2( r ),

= ( ( 230 rad / sec )^2 )( .175 m )...

= ( About ) 9290 m /

answer: option c. i.e. electric current flowing “downhill” from the negative electrode to the positive electrode in a battery

explanation:

the water analogy to the circuits define the pipes (water flows) to the electric current. now, we know that the electric current flows from the positive terminal to the circuit (as shown in the diagram attached).

hence, option c is the correct answer.

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.