A lunar module weighs 12 metric tons on the surface of the Earth. How much work is done in propelling the module from the surface of the moon to a height of 80 miles

149.05J

Explanation:

Hello,

Data;

Weight = 12N

x = 80miles

Radius of the moon = 1079.4mi

W = mg

But gravity at moon = ⅙ the gravity on earth

12 = ⅙ × m

M = 2kg

Mass of the module = 2kg

K = F.x

F(x) = k / x²

2 = k / (1079.4)²

k = 2.33×10⁶

Work = ∫f.dx

work = ∫₁₀₇₉.₄¹¹⁵⁹ . (2.33×10⁶/x²).dx

Work = (-2.33×10⁶) ×(¹/₁₁₅₉ - ¹/₁₀₇₉)

work = 149.05J

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this