1)Un niño dispara una piedra con una honda, verticalmente hacia arriba, desde la planta baja de un edificio, con una velocidad de 10 m/s. Calcular: a)¿A qué altura máxima llega la piedra respecto del suelo? b)¿Qué velocidad tendrá la piedra al segundo de haber sido lanzada?

a)   h_max = 5.10m

b)   v = 0.2 m/s

Explanation:

a) In order to calculate the maximum height reached by the rock, you use the following formula:

      (1)

vo: initial speed of the rock = ?

g: gravitational acceleration constant = 9.8m/s^2

You replace the values of the parameters in the equation (1):

The maximum height reached by the rock is 5.10m

b) The speed of the rock, one second after it was thrown is given by:

The speed of the rock is 0.2m/s

for this one it would be d bump/forearm pass