A grating having 5000 lines/cm is used with light of wavelength 633 nm. How many total maxima (count central maxima plus all those on either side of the central maxima) are produced

The  total number of maxima produced is   maxima

Explanation:

From the question we are told that

    The number of lines per cm is  

      The wavelength of the light is  

Now the distance between the lines is mathematically evaluated as

substituting values  

              N/B - this  statement convert it from  cm to m

Generally the condition for diffraction i mathematically represented as  

at maximum  

here m is the  number of  maxima  

      Thus  making  m the subject we have

So    

=>          m  =3  

  Now the total number of maxima would include the bright fringe(3) and  dark fringe (3) plus the central maxima (1)

Thus  

        maxima

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia