World-class sprinters can accelerate out of the starting blocks with an acceleration that is nearly horizontal and has magnitude 15m/s2. Part A How much horizontal force F must a sprinter of mass 47 kg exert on the starting blocks to produce this acceleration

The horizontal force the sprinter exerts on the starting blocks is 705 N

Explanation:

Given;

mass of the sprinter, m = 47 kg

magnitude of the his horizontal acceleration, aₓ = 15 m/s²

The horizontal force the sprinter exerts on the starting blocks to produce this acceleration, is calculated by applying Newton's second law of motion.

∑Fₓ = maₓ

∑Fₓ = 47 x 15

∑Fₓ = 705 N

Therefore, the horizontal force the sprinter exerts on the starting blocks is 705 N

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle