Physics, 15.07.2020 03:01 animegirl02
A 1.30-kg particle moves in the xy plane with a velocity of v with arrow = (4.50 î − 3.30 ĵ) m/s. Determine the angular momentum of the particle about the origin when its position vector is r with arrow = (1.50 î + 2.20 ĵ) m.
Answers: 3
![\vec l = -19.305\,k\,\left[kg\cdot \frac{m}{s} \right]](/tpl/images/0706/8884/e0f83.png)
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, ![\vec r = 1.50\,i + 2.20\,j\,[m]](/tpl/images/0706/8884/1820e.png)
and ![\vec v = 4.50\,i-3.30\,j\,\left[\frac{m}{s} \right]](/tpl/images/0706/8884/b5354.png)
, the angular momentum of the particle about the origin is:![\vec l = (1.30\,kg)\cdot \left[\left(1.50\,m\right)\cdot\left(-3.30\,\frac{m}{s} \right)-\left(2.20\,m\right)\cdot\left(4.50\,\frac{m}{s} \right)\right]k](/tpl/images/0706/8884/7731a.png)
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A 1.30-kg particle moves in the xy plane with a velocity of v with arrow = (4.50 î − 3.30 ĵ) m/s. De...
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