Physics, 14.07.2020 23:01 prettyluhangel

You throw a Frisbee of mass m and radius r so that it is spinning about a horizontal axis perpendicular to the plane of the Frisbee. Ignoring air resistance, the torque exerted about its center of mass by gravity is

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Answer from: dajahj27

following are the response to the given question:

The torque is calculated as the product of the pressure and also the perpendicular distance between both the force and the axis.In this case, gravity acts at the center, as well as the rotational axis likewise passes through it.As a result, the perpendicular distance between both the force and the rotational axis is 0.

Calculating the torque:

$\text{= Force} \times \text{Perpendicular distance}$

Therefore, the final torque would be '0'.

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Answer from: Quest

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Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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You throw a Frisbee of mass m and radius r so that it is spinning about a horizontal axis perpendicu...