Guys I'm in kind of PICKLE I know people say it a lot but I will give Brainiest to the best explained answer. Determine the net force charge acting at q1 (+ 2.0 × 10-5C), caused by q2 (-4.0 × 10-5 C) and q3 (-4.0 × 10-5 Determine the net electric field acting at q1

a) Fnet = 176.78N

b) Enet = 88.39 × 10⁵N/C

Explanation:

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards