a sandbag is released from a rising air balloon and hits the ground 7 seconds later. from what height was the sandbag dropped from if at teh moment of release the balloon was traveling upward at 3m/s

0.46

Explanation:

We can solve this problem using the suvat equations of motions.

the height, s is what we are trying to find out

initial velocity, u = 3 m/s  from the question

final velocity, v = 0 m/s since it hits the ground it will stop moving downwards

acceleration, a = -9.81, due to gravity

time, t =7, from the question.

v² = u² + 2as ⇒ v²-u² = 2as

                     ⇒ s =

                     ⇒ s =

                     ⇒ s = 9/19.62

                     ⇒ s ≈ 0.46

i sometimes feel that way too. i feel that i should hurt someone because they hurt me, but i wouldnt do it. that would make things so much worse i have so much experience with this stuff

explanation:

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2